TYPICAL CHARACTERISTICS: VS = ±5V

5

4

3

2

1

0

-1

-2

-3

-4

-5

-6

Frequency(Hz)

1M

2G

10M

100M

1G

V = 5V

±

V

=0.5V

R

=100W

S

O

PP

LOAD

G=+1,R =511W

F

G=+16,R =249W

F

G=+8,R =402W

F

G=+2,R =511W

F

G=+4,R =511W

F

2

1

0

-1

-2

-3

-4

-5

-6

Frequency(Hz)

1M

1G

100M

V = 5V

±

G=+2V/V

R =511

R

=100

W

W

S

F

LOAD

V

=7V

O

PP

V

=4V

O

PP

V

=2V

O

PP

V

=1V

O

PP

1

0

-1

-2

-3

-4

Frequency(Hz)

1M

1G

100M

V =±5V

G=+8V/V

R =402

R

=100

W

W

S

F

LOAD

V

=1V

O

PP

V

=2V

O

PP

V

=4V

O

PP

V

=7V

O

PP

600

400

200

0

-200

-400

-600

Time(ns)

0

11

1

2

3

4

5

6

7

8

9

10

V =±5V

G=+8V/V

R =402

R

=100

W

W

S

F

LOAD

2.5

2.0

1.5

1.0

0.5

0

-0.5

-1.0

-1.5

-2.0

-2.5

Time(ns)

0

11

1

2

3

4

5

6

7

8

9

10

V =±5V

G=+8V/V

R =402

R

=100

W

W

S

F

LOAD

-60

-65

-70

-75

-80

-85

-90

-95

LoadResistance( )

W

1

1k

100

3rdHarmonic

2ndHarmonic

V = 5V

±

G=+8V/V

R =402

V

=2V

W

S

F

OUT

PP

OPA3695

www.ti.com ............................................................................................................................................... SBOS355A – APRIL 2008 – REVISED SEPTEMBER 2008

At RF = 402Ω, RL = 100Ω, and G = +8, unless otherwise noted.

NONINVERTING SMALL-SIGNAL FREQUENCY RESPONSE

GAIN OF +2, LARGE-SIGNAL FREQUENCY RESPONSE

Figure 2.

Figure 3.

GAIN OF +8, LARGE-SIGNAL FREQUENCY RESPONSE

NONINVERTING SMALL-SIGNAL PULSE RESPONSE

Figure 4.

Figure 5.

NONINVERTING LARGE-SIGNAL PULSE RESPONSE

10MHz HARMONIC DISTORTION vs LOAD RESISTANCE

Figure 6.

Figure 7.

Copyright © 2008, Texas Instruments Incorporated

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