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LT3579 Datasheet(PDF) 29 Page - Linear Technology

Part # LT3579
Description  6A Boost/Inverting DC/DC Converter with Fault Protection
PDF  40 Pages
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Manufacturer  LINER [Linear Technology]
Direct Link  http://www.linear.com
Logo LINER - Linear Technology

LT3579 Datasheet(HTML) 29 Page - Linear Technology

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LT3579/LT3579-1
29
35791f
feedback loop.
As with any feedback loop, identifying the gain and phase
contribution of the various elements in the loop is critical.
Figure 18 shows the key equivalent elements of a boost
converter. Because of the fast current control loop, the
powerstageoftheIC,inductoranddiodehavebeenreplaced
by a combination of the equivalent transconductance
amplifier gmp and the current controlled current source
(which converts IVIN to ηVIN
VOUT
IVIN
). Gmp acts as a current
APPENDIX
1.215V
REFERENCE
IVIN
• VIN
VOUT
• IVIN
VOUT
COUT
CPL
RESR
RL
RO
RC
CC
CF
R1
FB
R2
R2
–
+
3579 F18
gmp
gma
CC: COMPENSATION CAPACITOR
COUT: OUTPUT CAPACITOR
CPL: PHASE LEAD CAPACITOR
CF: HIGH FREQUENCY FILTER CAPACITOR
gma: TRANSCONDUCTOR AMPLIFIER INSIDE IC
gmp: POWER STAGE TRANSCONDUCTANCE AMPLIFIER
RC: COMPENSATION RESISTOR
RL: OUTPUT RESISTANCE DEFINED AS VOUT/ILOADMAX
RO: OUTPUT RESISTANCE OF gma
R1, R2; FEEDBACK RESISTOR DIVIDER NETWORK
RESR: OUTPUT CAPACITOR ESR
: CONVERTER EFFICIENCY (~90% AT HIGHER CURRENTS)
Figure 18. Boost Converter Equivalent Model
source where the peak input current, IVIN, is proportional
to the VC voltage.
Note that the maximum output currents of gmp and gma
are finite. The output of the gmp stage is limited by the
minimum switch current limit (see Electrical Specifications)
and gma is nominally limited to about ±12μA.
From Figure 18, the DC gain, poles and zeros can be
calculated as follows:
DC Gain
Ag
R
g
V
V
RR
R
DC
ma
O
mp
IN
OUT
L
:
.
=•
•
• •
•
•
η
2
05
2
1+
+
=
••
•
05
1
2
2
2
.
:
R
Output Pole P
RC
Error Amp Po
L
OUT
π
lle P
RR
C
Error Amp Zero Z
OC
C
:
:
2
1
2
1
1
2
=
••
+
()•
=
••
π
π R
RC
ESR Zero Z
RC
RHP Zero Z
V
CC
ESR
OUT
•
=
••
•
=
:
:
2
1
2
3
π
IIN
L
OUT
S
R
VL
High Frequency Pole P
f
P
2
2
2
3
3
•
••
•
>
π
:
h
hase Lead Zero Z
RC
Phase Lead Pole P
PL
:
:
4
1
2
1
=
•• •
π
4
4
1
2
05
05
12
12
=
••
•
+
•
π
RR
RR
C
Error Amp Filter P
PL
.
.
o
ole
P
RR
RR
C
C
C
CO
CO
F
F
C
:
,
5
1
2
10
=
••
•
+
<
π



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