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OPA690 Datasheet(PDF) 16 Page - Texas Instruments |
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OPA690 Datasheet(HTML) 16 Page - Texas Instruments |
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16 / 33 page ![]() OPA699 16 SBOS261D www.ti.com WIDEBAND INVERTING OPERATION Operating the OPA699 as an inverting amplifier has several benefits and is particularly useful when a matched 50 Ω source and input impedance are required. Figure 3 shows the inverting gain of –4V/V circuit used as the basis of the inverting mode typical characteristics. LOW-GAIN COMPENSATION FOR IMPROVED SFDR Where a low gain is desired, and inverting operation is acceptable, a new external compensation technique can be used to retain the full slew rate and noise benefits of the OPA699, while giving increased loop gain and the associ- ated distortion improvements offered by a non-unity-gain stable op amp. This technique shapes the loop gain for good stability, while giving an easily controlled 2nd-order low-pass frequency response. To set the compensation capacitors (CS and CF), consider the half-circuit of Figure 5, where the 50Ω source is used. Considering only the noise gain for the circuit of Figure 5, the low-frequency noise gain (NG1) is set by the resistor ratio, while the high-frequency noise gain (NG2) is set by the capacitor ratio. The capacitor values set both the transition frequencies and the high-frequency noise gain. If the high- frequency noise gain, determined by NG2 = 1 + CS/CF, is set to a value greater than the recommended minimum stable gain for the op amp, and the noise gain pole (set by 1/RFCF) is placed correctly, a very well controlled 2nd-order low-pass frequency response results. In the inverting case, only the feedback resistor appears as part of the total output load in parallel with the actual load. For a 500 Ω load used in the typical characteristics, this gives a total load of 329 Ω in this inverting configuration. The gain resistor is set to get the desired gain (in this case, 187 Ω for a gain of –4) while an additional input resistor (RM) can be used to set the total input impedance equal to the source, if desired. In this case, RM = 68.1Ω in parallel with the 187Ω gain setting resistor gives a matched input impedance of 50 Ω. This matching is only needed when the input needs to be matched to a source impedance, as in the characteriza- tion testing done using the circuit of Figure 3. For bias current-cancellation matching, the noninverting input requires a 169 Ω resistor to ground. The calculation for this resistor includes a DC-coupled 50 Ω source impedance along with RG and RM. Although this resistor will provide cancella- tion for the bias current, it must be well-decoupled (0.1 µF in Figure 3) to filter the noise contribution of the resistor and the input current noise. As the required RG resistor approaches 50Ω at higher gains, the bandwidth for the circuit in Figure 3 will far exceed the bandwidth at that same gain magnitude for the noninverting circuit of Figure 1. This occurs due to the lower noise gain for the circuit of Figure 3 when the 50 Ω source impedance is included in the analysis. For instance, at a signal gain of –15 (RG = 50Ω, RM = open, RF = 750Ω) the noise gain for the circuit of Figure 3 will be 1 + 750 Ω/(50Ω + 50Ω) = 8.5 due to the addition of the 50 Ω source in the noise gain equation. This approach gives considerably higher bandwidth than the noninverting gain of +15. Using the 1GHz gain bandwidth product for the OPA699, an inverting gain of –15 from a 50 Ω source to a 50 Ω R G will give 140MHz bandwidth, whereas the noninverting gain of +8 will give 55MHz, as shown in the measured results of Figure 4. OPA699 –5V V I –2V +5V +2V R M 68.1 Ω R F 750 Ω R G 187 Ω 500 Ω 0.1 µF R T 169 Ω V H V L V O 50 Ω Source 1M 10M 100M 1G Frequency (Hz) 24 21 18 15 12 9 G = +15 G = –15 R F 402 Ω C S 13pF OPA699 +5V –5V V O V I C F 2.8pF 200 Ω R G 402 Ω V H V L FIGURE 3. Inverting G = –4 Specifications and Test Circuit. FIGURE 4. G = +15 and –15 Frequency Response. FIGURE 5. Broadband, Low-Inverting Gain External Compensation. |
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