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LM4854 Datasheet(PDF) 23 Page - National Semiconductor (TI) |
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LM4854 Datasheet(HTML) 23 Page - National Semiconductor (TI) |
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23 / 29 page ![]() Application Information (Continued) OPTIMIZING CLICK AND POP REDUCTION PERFOR- MANCE The LM4854 contains circuitry that eliminates turn-on and shutdown transients ("clicks and pops") and transients that could occur when switching between BTL speakers and single-ended headphones. For this discussion, turn-on re- fers to either applying the power supply voltage or when the micro-power shutdown mode is deactivated. As the V DD/2 voltage present at the BYPASS pin ramps to its final value, the LM4854’s internal amplifiers are configured as unity gain buffers and are disconnected from the L-OUT, BTL-OUT, and R-OUT pins. An internal current source charges the capacitor connected between the BYPASS pin and GND in a controlled, linear manner. Ideally, the input and outputs track the voltage applied to the BYPASS pin. The gain of the internal amplifiers remains unity until the voltage on the bypass pin reaches V DD/2. Once the voltage on the bypass pin is stable and after a fixed nominal delay of 120ms, the device becomes fully operational and the ampli- fier outputs are reconnected to their respective output pins. Although the BYPASS pin current cannot be modified, changing the size of CB alters the device’s turn-on time. There is a linear relationship between the size of CB and the turn-on time. Here are some typical turn-on times for various values of CB: C B (µF) T ON (ms) 0.01 120 0.1 130 0.22 140 0.47 160 1.0 200 2.2 300 In order eliminate "clicks and pops", all capacitors must be discharged before turn-on. Rapidly switching V DD may not allow the capacitors to fully discharge, which may cause "clicks and pops". AUDIO POWER AMPLIFIER DESIGN Audio Amplifier Design: Driving 1W into an 8 Ω Load The following are the desired operational parameters: • Power Output: 1W RMS • Load Impedance 8 Ω • Input Level: 1V RMS • Input Impedance: 20k Ω • Bandwidth: 100Hz - 20kHz ± 0.25dB The design begins by specifying the minimum supply voltage necessary to obtain the specified output power. One way to find the minimum supply voltage is to use the Output Power vs Supply Voltage curve in the Typical Performance Charac- teristics section. Another way, using Equation (8), is to cal- culate the peak output voltage necessary to achieve the desired output power for a given load impedance. To ac- count for the amplifier’s dropout voltage, two additional volt- ages, based on the Dropout Voltage vs Supply Voltage in the Typical Performance Characteristics curves, must be added to the result obtained by Equation (8). The result is Equation (9). (8) V DD =VOUTPEAK +VODTOP +VODBOT (9) The Output Power vs. Supply Voltage graph for an 8 Ω load indicates a minimum supply voltage of 4.6V. The commonly used 5V supply voltage easily meets this. The additional voltage creates the benefit of headroom, allowing the LM4854 to produce peak output power in excess of 1W without clipping or other audible distortion. The choice of supply voltage must also not create a situation that violates of maximum power dissipation as explained above in the Power Dissipation section. After satisfying the LM4854’s power dissipation requirements, the minimum differential gain needed to achieve 1W dissipation in an 8 Ω load is found using Equation (10). (10) Thus, a minimum gain of 2.83 allows the LM4854’s to reach full output swing and maintain low noise and THD+N perfor- mance. For this example, let AVD = 3. The amplifier’s overall gain is set using the input (R i) and feedback (Rf) resistors. With the desired input impedance set at 20k Ω, the feedback resistor is found using Equation (11). R f /Ri =AVD / 2 (11) The value of R f is 30k Ω. The nominal output power is 1.13W. TThe last step in this design example is setting the amplifi- er’s -3dB frequency bandwidth. To achieve the desired ±0.25dB pass band magnitude variation limit, the low fre- quency response must extend to at least one-fifth the lower bandwidth limit and the high frequency response must ex- tend to at least five times the upper bandwidth limit. The gain variation for both response limits is 0.17dB, well within the ±0.25dB-desired limit. The results are an f L = 100Hz / 5 = 20Hz (12) and an f L = 20kHz x 5 = 100kHz (13) As mentioned in the SELECTING EXTERNAL COMPO- NENTS section, R i and Ci create a highpass filter that sets the amplifier’s lower bandpass frequency limit. Find the cou- pling capacitor’s value using Equation (14). C i =1/(2 πR ifL) (14) The result is 1/(2 π x 20kΩ x 20Hz) = 0.397µF (15) Use a 0.39µF capacitor, the closest standard value. www.national.com 23 |
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