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SH7672 Datasheet(PDF) 243 Page - Renesas Technology Corp |
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SH7672 Datasheet(HTML) 243 Page - Renesas Technology Corp |
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243 / 1292 page ![]() Section 7 Bus State Controller (BSC) Rev. 1.00 Nov. 14, 2007 Page 217 of 1262 REJ09B0437-0100 7.5 Operation 7.5.1 Endian/Access Size and Data Alignment This LSI supports both big endian, in which the most significant byte (MSB) of data is that in the direction of the 0th address, and little endian, in which the least significant byte (LSB) is that in the direction of the 0th address. In the initial state after a power-on reset, all areas will be in big endian mode. Little endian cannot be selected for area 0. However, the endian of areas 3 to 6 can be changed by the setting in the CSnBCR register setting as long as the target space is not being accessed. Three data bus widths (8 bits, 16 bits, and 32 bits) are selectable for areas 3 to 6, allowing the connection of normal memory and of SRAM with byte selection. Two data bus widths (16 bits and 32 bits) are available for SDRAM. Two data bus widths (8 bits and 16 bits) are available for the PCMCIA interface. For MPX-I/O, the data bus width can be fixed to either 8 or 16 bits, or made selectable as 8 bits or 16 bits by one of the address lines. Data alignment is in accord with the data bus width selected for the device. This also means that four read operations are required to read longword data from a byte-width device. In this LSI, data alignment and conversion of data length is performed automatically between the respective interfaces. The data bus width of area 0 is fixed to 8 bits or 16 bits by the MD_BW pin setting at a power-on reset. Tables 7.5 to 7.10 show the relationship between device data width and access unit. Note that the correspondence between addresses and strobe signals for the 32- and 16-bit bus widths depends on the endian setting. For example, with big endian and a 32-bit bus width, WE3 corresponds to the 0th address, which is represented by WE0 when little endian has been selected. Little endian cannot be selected for area 0. Note also that 32-bit and 16-bit accesses coincide in instruction fetching, therefore, it is difficult to allocate instruction to little endian area. Make sure to execute instruction in big endian area. |
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