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AN2450 Datasheet(PDF) 5 Page - STMicroelectronics

Part # AN2450
Description  LLC resonant half-bridge converter design guideline
PDF  35 Pages
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Manufacturer  STMICROELECTRONICS [STMicroelectronics]
Direct Link  http://www.st.com
Logo STMICROELECTRONICS - STMicroelectronics

AN2450 Datasheet(HTML) 5 Page - STMicroelectronics

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DocID12784 Rev 6
5/35
AN2450
FHA circuit model
35
whose fundamental component vi.FHA(t) (in phase with the original square waveform) is:
Equation 2
where fsw is the switching frequency. The rms value Vi.FHA of the input voltage fundamental
component is:
Equation 3
As a consequence of the above mentioned assumptions, the resonant tank current irt(t) will
be also sinusoidal, with a certain rms value Irt and a phase shift  with respect to the
fundamental component of the input voltage:
Equation 4
This current lags or leads the voltage, depending on whether inductive reactance or
capacitive reactance dominates in the behavior of the resonant tank in the frequency region
of interest. Irrespective of that, irt(t) can be obtained as the sum of two contributes, the first
in phase with the voltage, the second with 90° phase-shift with respect to it.
The dc input current Ii.dc from the dc source can also be found as the average value, along
a complete switching period, of the sinusoidal tank current flowing during the high-side
MOSFET conduction time, when the dc input voltage is applied to the resonant tank:
Equation 5
where Tsw is the time period at switching frequency.
The real power Pin, drawn from the dc input source (equal to the output power Pout in this
ideal case) can now be calculated as both the product of the input dc voltage Vdc times the
average input current Ii.dc and the product of the rms values of the voltage and current's first
harmonic, times cos
 :
Equation 6
the two expressions are obviously equivalent.
The expression of the apparent power Papp and the reactive power Pr are respectively:
Equation 7
viFHA t
2
---Vdc
2
f
swt

sin
=
.
viFHA
2
-------Vdc
=
.
irt t
2Irt
2
f
swt
–

sin
2Irt
cos
2
f
swt

2Irt
–
sin

2
f
swt

cos
sin
=
=
Iidc
1
Tsw
---------
irt t t
d
2
-------Irt
cos
=
0
Tsw
2
---------
=
.
Pin
VdcIidc ViFHAIrt
cos
=
=
.
.
Papp
ViFHAIrt
=
.
.
Pr
ViFHAIrt
sin
=



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