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ADP3182 Datasheet(PDF) 18 Page - Analog Devices |
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ADP3182 Datasheet(HTML) 18 Page - Analog Devices |
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18 / 20 page ![]() ADP3182 Rev. 0 | Page 18 of 20 A type three compensator on the voltage feedback is adequate for proper compensation of the output filter. Equations 20 to 22 are intended to yield an optimal starting point for the design; some adjustments may be necessary to account for PCB and component parasitic effects. DS D L OUT R X B X X A R A R V V R n R R C C × + × × × × × = 2 4 (17) ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ × × × − × × × × × × = X SW DS D OUT X R X X B A R f R A V R V L R C n R R 2 4 2 (18) A SW FB R f n C × × × = 2 1 (19) If CX is 6000 µF (five 1200 µF capacitors in parallel) with an equivalent ESR of 3 mΩ, the equations above give the following compensation values: CA = 1.33 nF RA = 6.05 kΩ CFB = 110 pF Using the nearest standard value for each of these components yields CA = 1.2 nF, RA = 6.04 kΩ, and CFB = 100 pF. INPUT CAPACITOR SELECTION AND INPUT CURRENT di/dt In continuous inductor current mode, the source current of the high-side MOSFET is approximately a square wave with a duty ratio equal to n × VOUT/VIN and an amplitude of one-nth the maximum output current. To prevent large voltage transients, a low ESR input capacitor, sized for the maximum rms current, must be used. The maximum rms capacitor current is given by A 1 . 9 1 5 0.1 3 1 A 55 15 . 0 1 1 = − × × × = − × × × = CRMS O CRMS I D N I D I (20) Note that manufacturers often base capacitor ripple current rating on only 2,000 hours of life. Therefore, it advisable to further derate the capacitor or to choose a capacitor rated at a higher temperature than required. Several capacitors may be placed in parallel to meet size or height requirements in the design. In this example, the input capacitor bank is formed by two 2,700 µF, 16 V aluminum electrolytic capacitors and three 4.7 µF ceramic capacitors. To reduce the input current di/dt to a level below the recom- mended maximum of 0.1 A/µs, an additional small inductor (L > 370 nH @ 10 A) can be inserted between the converter and the supply bus. That inductor also acts as a filter between the converter and the primary power source. INDUCTOR DCR TEMPERATURE CORRECTION With the inductor’s DCR being used as the sense element and copper wire being the source of the DCR, one needs to compensate for temperature changes in the inductor’s winding if a highly accurate safety current limit setpoint is desired. Fortunately, copper has a well-known temperature coefficient (TC) of 0.39%/°C. If RCS is designed to have an opposite and equal percentage of change in resistance to that of the wire, it cancels the tempera- ture variation of the inductor’s DCR. Due to the nonlinear nature of NTC thermistors, resistors RCS1 and RCS2 are needed. See Figure 10 for instructions on how to linearize the NTC and produce the desired temperature tracking. 17 ADP3182 CSCOMP CSSUM CSREF RTH RCS1 RCS2 CCS1 CCS2 RPH1 RPH2 RPH3 TO SWITCH NODES TO VOUT SENSE PLACE AS CLOSE AS POSSIBLE TO NEAREST INDUCTOR OR LOW-SIDE MOSFET KEEP THIS PATH AS SHORT AS POSSIBLE AND WELL AWAY FROM SWITCH NODE LINES 18 16 Figure 10. Temperature Compensation Circuit Values The following procedures and expressions yield values to use for RCS1, RCS2, and RTH (the thermistor value at 25°C) for a given RCS value. 1. Select an NTC based on type and value. Because we do not have a value yet, start with a thermistor with a value close to RCS. The NTC should also have an initial tolerance of better than 5%. 2. Based on the type of NTC, find its relative resistance value at two temperatures. The temperatures that work well are 50°C and 90°C. These resistance values are called A (RTH(50°C)/RTH(25°C)) and B (RTH(90°C)/RTH(25°C)). Note that the NTC’s relative value is always 1 at 25°C. 3. Find the relative value of RCS required for each of these temperatures. This is based on the percentage of change needed, which in this example is initially 0.39%/°C. These are called r1 (1/(1 + TC × (T1 − 25))) and r2 (1/(1 + TC × (T2 − 25))), where TC = 0.0039 for copper. T1 = 50°C and T2 = 90°C are chosen. From this, one can calculate that r1 = 0.9112 and r2 = 0.7978. 4. Compute the relative values for RCS1, RCS2, and RTH using ( ) () ( ) () () ( ) B A r A B r B A r A B r B A r r B A r 2 1 1 2 2 1 CS2 − − × − × − × − × × − × + × − × − × × − = 1 1 1 1 (21) |
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