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INA210 Datasheet(PDF) 23 Page - Texas Instruments

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Part # INA210
Description  High or Low Side, Bi-Directional CURRENT/POWER MONITOR with Two-Wire Interface
PDF  39 Pages
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Manufacturer  TI1 [Texas Instruments]
Direct Link  http://www.ti.com
Logo TI1 - Texas Instruments

INA210 Datasheet(HTML) 23 Page - Texas Instruments

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INA220
www.ti.com
SBOS459D – JUNE 2009 – REVISED SEPTEMBER 2010
The Current Register (04h) is then calculated by
this result by the power LSB that is 20 times the
multiplying
the
shunt
voltage
contents
by
the
1 × 10-3 current LSB, or 20 × 10-3, results in a power
Calibration Register and then dividing by 4095. For
calculation
of
5991
×
20mW/bit,
which
equals
this example, the shunt voltage of 2000 is multiplied
119.82W. This result matches what is expected for
by the calibration register of 20480 and then divided
this register. A manual calculation for the power being
by 4095 to yield a Current Register of 2712h.
delivered to the load would use 11.98V (12VCM –
20mV shunt drop) multiplied by the load current of
The Power Register (03h) is then be calculated by
10A to give a 119.8W result.
multiplying the Current Register of 10002 by the Bus
Voltage Register of 2995 and then dividing by 5000.
Table 2 shows the steps for configuring, measuring,
For this example, the Power Register contents are
and calculating the values for current and power for
1767h, or a decimal equivalent of 5991. Multiplying
this device.
Table 2. Configure/Measure/Calculate Example(1)
STEP #
REGISTER NAME
ADDRESS
CONTENTS
ADJ
DEC
LSB
VALUE
Step 1
Configuration
00h
019Fh
Step 2
Shunt
01h
07D0h
2000
10µV
20mV
Step 3
Bus
02h
5D98h
0BB3
2995
4mV
11.98V
Step 4
Calibration
05h
5000h
20480
Step 5
Current
04h
2712h
10002
1mA
10.002A
Step 6
Power
03h
1767h
5991
20mW
119.82W
(1)
Conditions: load = 10A, VCM = 12V, RSHUNT = 2mΩ, VSHUNT FSR = 40mV, and VBUS = 16V.
Copyright © 2009–2010, Texas Instruments Incorporated
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