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CS5460 Datasheet(PDF) 12 Page - Cirrus Logic

Part # CS5460
Description  Single Phase Bi-Directional Power/Energy IC
PDF  34 Pages
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Manufacturer  CIRRUS [Cirrus Logic]
Direct Link  http://www.cirrus.com
Logo CIRRUS - Cirrus Logic

CS5460 Datasheet(HTML) 12 Page - Cirrus Logic

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CS5460
12
DS279PP5
2.4 Pulse-Rate Output
As an alternative to reading the energy through the
serial port, the EOUT and EDIR pins provide a
simple interface with which signed energy can be
accumulated. Each EOUT pulse represents a prede-
termined magnitude of energy. The accompanying
EDIR level represents the sign of the energy. With
MCLK = 4.096 MHz, K = 1, and both ADC inputs
at their maximum DC values, the pulses will have
a frequency equal to that in the pulse rate register.
The following example illustrates how to calculate
the pulse-rate register contents for a given meter
design. Suppose that a single two-phase power
meter (Figure 3) is required to generate 500 impuls-
es/KWH at Ib = 20 ARMS and V = 230 VRMS. As-
sume that the maximum current is Imax = 100 ARMS
and the maximum voltage is Vmax= 300 VRMS. To
utilize the full dynamic range of the CS5460, the
sensor gains can be calculated as:
where kv and ki are the sensor gains for the voltage
and current, respectively. The CS5460 is assumed
to be in the 30 mVRMS range to allow for the use of
a shunt resistor.
The average Impulse Rate, IR, at the rated inputs is:
Since the pulse-rate register is defined in terms of
full-scale DC (0.25 V for the voltage channel and
0.05 V for the current channel in this case), IR will
need to be scaled before being placed in the
pulse-rate register. Define a voltage ratio, Rv, and
a current ratio, Ri, as:
-2.5
-2.0
-1.5
-1.0
-0.5
0.0
0.5
Frequency (Hertz)
0
200
400
600
800
1000 1200 1400
1600 1800 2000
Figure 6. Voltage Input Filter Roll-off
-2.5
-2
-1.5
-1
-0.5
0
0.5
0
200
400
600
800
1000
1200
1400
1600
1800
2000
Frequency (Hertz)
Figure 7. Current Input Filter Roll-off
k
v
150mV
RM S
V
max
-----------------------------
1
2000
------------
==
k
i
30mV
RMS
I
ma x
--------------------------
300
µΩ
==
R
500 impulses
KWH
--------------------------------


I
bV
()
1KW
1000W
------------------

 1H
3600s
--------------


=
0.639 impulses
s
------------------------------------
≅
R
v
0.25 Volt
k
vV Volt
-----------------------
=
R
i
0.05 Volt
k
iIb Amp
-----------------------
=



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