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LM3673 Datasheet(PDF) 14 Page - Texas Instruments

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Part # LM3673
Description  2-MHz, 350-mA Step-Down DC-DC Converter
PDF  28 Pages
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Manufacturer  TI [Texas Instruments]
Direct Link  http://www.ti.com
Logo TI - Texas Instruments

LM3673 Datasheet(HTML) 14 Page - Texas Instruments

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Fp =
1
2 * S * (R1 R2) * (C1+C2)
Fz =
1
(2 * S * R1 * C1)
C2 =
1
(2 * S * R2 * 45 kHz)
C1 =
1
(2 * S * R1 * 45 kHz)
VOUT = VFB
1 +
R1
R2
¹
·
©
§
LM3673
SNVS434L – JULY 2006 – REVISED OCTOBER 2015
www.ti.com
9.2.2 Detailed Design Procedure
9.2.2.1 Output Voltage Selection for LM3673-ADJ
The output voltage of the adjustable device can be programmed through the resistor network connected from
VOUT to FB, then to GND. VOUT is adjusted to make the voltage at FB equal to 0.5 V. The resistor from FB to
GND (R2) must be 200 k
Ω to keep the current drawn through this network well below the 16-µA quiescent
current level (PFM mode) but large enough that it is not susceptible to noise. If R2 is 200 k
Ω, and VFB is 0.5 V,
the current through the resistor feedback network is 2.5 µA. The output voltage of the adjustable device ranges
from 1.1 V to 3.3 V.
The formula for output voltage selection is:
where
•
VOUT: output voltage (V)
•
VFB : feedback voltage = 0.5 V
•
R1: feedback resistor from VOUT to FB
•
R2: feedback resistor from FB to GND
(2)
For any output voltage greater than or equal to 1.1 V, a zero must be added around 45 kHz for stability. The
formula for calculation of C1 is:
(3)
For output voltages higher than 2.5 V, a pole must be placed at 45 kHz as well. If the pole and zero are at the
same frequency the formula for calculation of C2 is:
(4)
The formula for location of zero and pole frequency created by adding C1 and C2 is shown in Equation 5 and
Equation 6. By adding C1, a zero as well as a higher frequency pole is introduced.
(5)
(6)
See Table 2.
14
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