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MAX1997 Datasheet(PDF) 27 Page - Maxim Integrated Products |
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MAX1997 Datasheet(HTML) 27 Page - Maxim Integrated Products |
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27 / 31 page ![]() Quintuple/Triple-Output TFT LCD Power Supplies with Fault Protection and VCOM Buffer ______________________________________________________________________________________ 27 Stability Requirements The MAX1997/MAX1998 linear-regulator controllers use an internal transconductance amplifier to drive an external pass transistor. The transconductance amplifi- er, the pass transistor, the base-emitter resistor, and the output capacitor determine the loop stability. The transconductance amplifier regulates the output voltage by controlling the pass transistor’s base cur- rent. The total DC loop gain is approximately: where VT is 26mV at room temperature, hFE is the pass transistor’s DC current gain, and IBIAS is the current through the base-to-emitter resistor (RBE). Each of the four linear-regulator controllers is designed for a differ- ent maximum output current so they have different out- put drive currents and different bias currents (IBIAS). Each controller’s bias current can be found in the Electrical Characteristics. The current listed in the Conditions column for the FB_ Regulation Voltage specification is the individual controller’s bias current. The base-to-emitter resistor for each controller should be chosen to set the correct IBIAS: The output capacitor and the load resistance create the dominant pole in the system. However, the internal amplifier delay, the pass transistor’s input capacitance, and the stray capacitance at the feedback node create additional poles in the system, and the output capacitor’s ESR generates a zero. For proper operation, use the following steps to ensure the linear regulator stability: 1) First, calculate the dominant pole set by the linear regulator’s output capacitor and the load resistor: where CLDO is the output capacitance of the LDO and RLOAD is the load resistance corresponding to the maximum load current. The unity gain crossover of the linear regulator is: fCROSSOVER = AV(LDO)fPOLE(LDO) 2) The pole caused by the internal amplifier delay is at about 1MHz: fPOLE(AMP) ≅ 1MHz 3) Next, calculate the pole set by the transistor’s input capacitance, the transistor’s input resistance, and the base-to-emitter pullup resistor: Because RBE is much greater than RIN, the above equation can be simplified: where gm is the transconductance of the pass tran- sistor, and fT is the transition frequency. Both para- meters can be found in the transistor’s data sheet. Therefore, the equation can be further simplified: 4) Next, calculate the pole set by the linear regulator’s feedback resistance and the capacitance between FB_ and GND (approximately 5pF including stray capacitance): and 5) Next, calculate the zero caused by the output capacitor’s ESR: where RESR is the equivalent series resistance of CLDO. f CR ESR ZERO LDO ESR _ = 1 2 π f CR R POLE FB N FB ()_ (|| ) = 1 216 17 π f CR R f CR R f CR R POLE FB P FB POLE FB FB POLE FB FB ()_ ()_ ()_ (|| ) (|| ) (|| ) = = = 1 219 20 1 288 99 1 211 12 1 2 π π π f f POLE(CIN) T = hFE f 1 C g h g POLE(CIN) II m I FE m ≈ = == 2 2 π π π CR f RR NN IN T N f 1 I) POLE(CIN) BE IN = 2 πCN R R II ( f 1 POLE(LDO) LDO LOAD = 2 πCR R V BE BE BIAS = I A 4 V h I V V(LDO) T BIAS FE LOAD REF = + 1 I |
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