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TPS610333 Datasheet(PDF) 17 Page - Texas Instruments |
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TPS610333 Datasheet(HTML) 17 Page - Texas Instruments |
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17 / 28 page ![]() OUT REF V R1 1 R2 V § · u ¨ ¸ © ¹ (5) where • VOUT is the regulated output voltage • VREF is the internal reference voltage at the FB pin For the best accuracy, should be kept R2 smaller than 300 kΩ to ensure the current flowing through R2 is at least 100 times larger than the FB pin leakage current. Changing R2 towards a lower value increases the immunity against noise injection. Changing the R2 towards a higher value reduces the quiescent current for achieving highest efficiency at low load currents. 9.2.2.2 Inductor Selection Because the selection of the inductor affects steady-state operation, transient behavior, and loop stability. The inductor is the most important component in power regulator design. There are three important inductor specifications, inductor value, saturation current, and dc resistance (DCR). The TPS61033 is designed to work with inductor values between 0.37 µH and 2.9 µH. Follow Equation 6 to Equation 8 to calculate the inductor peak current for the application. To calculate the current in the worst case, use the minimum input voltage, maximum output voltage, and maximum load current of the application. To have enough design margins, choose the inductor value with –30% tolerances, and low power-conversion efficiency for the calculation. In a boost regulator, the inductor dc current can be calculated by Equation 6. OUT OUT L DC IN V I I V u u K (6) where • VOUT is the output voltage of the boost converter • IOUT is the output current of the boost converter • VIN is the input voltage of the boost converter • η is the power conversion efficiency, use 90% for most applications The inductor ripple current is calculated by Equation 7. IN L P P SW V D I L f u ' u (7) where • D is the duty cycle, which can be calculated by Equation 3 • L is the inductance value of the inductor • fSW is the switching frequency • VIN is the input voltage of the boost converter Therefore, the inductor peak current is calculated by Equation 8. L P P L P L DC I I I 2 ' (8) Normally, it is advisable to work with an inductor peak-to-peak current of less than 40% of the average inductor current for maximum output current. A smaller ripple from a larger valued inductor reduces the magnetic hysteresis losses in the inductor and EMI. But in the same way, load transient response time is increased. The www.ti.com TPS61033 SLVSGI6 – OCTOBER 2022 Copyright © 2022 Texas Instruments Incorporated Submit Document Feedback 17 Product Folder Links: TPS61033 |
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