PM7347 datasheet(58/341 Pages) PMC

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S/UNI®-JET Data Sheet

Released

Proprietary and Confidential to PMC-Sierra, Inc., and for its Customers’ Internal Use

Document ID: PMC-1990267, Issue 3

E3 LOF detection is provided as recommended by ITU-T G.783 with programmable integration

periods of 1 ms, 2 ms, or 3 ms. While integrating up to assert LOF, the counter will integrate up

when the framer asserts an OOF condition and integrates down when the framer de-asserts the

OOF condition. Once an LOF is asserted, the framer must not assert OOF for the entire

integration period before LOF is de-asserted.

The E3-FRMR can also be enabled to automatically assert the RAI/FERF indication in the

outgoing transmit stream upon detection of any combination of LOS, OOF or AIS. The

E3-FRMR can also be enabled to automatically insert G.832 FEBE upon detection of receive

BIP-8 errors.

10.3

J2 Framer

The J2-FRMR integrates circuitry to decode a unipolar or B8ZS encoded signal and frame to the

resulting 6312 kbps J2 bit stream. Having found frame, the J2-FRMR extracts a variety of

overhead and datalink information from the J2 bit stream.

The J2 format consists of 789-bit frames, each 125 µs long, consisting of 96 bytes of payload, 2

reserved bytes, and five F-bits. The frames are grouped into 4-frame multiframes. The multiframe

format is described in Table 4.

Table 4 Multiframe Format

Bit

1-8

761-768

769-776

777-784

785

786

787

788

789

TS1[1:8]

TS96[1:8]

TS97[1:8]

TS98[1:8]

TS1[1:8]

TS96[1:8]

TS97[1:8]

TS98[1:8]

TS1[1:8]

TS96[1:8]

TS97[1:8]

TS98[1:8]

TS1[1:8]

TS96[1:8]

TS97[1:8]

TS98[1:8]

Notes

TS1 . TS96 are the byte interleaved payloads.

TS97, TS98 are reserved channels for signaling.

The Frame Alignment Signal is represented as binary ones and zeroes.

10. m is a 4-kHz datalink.

11. x1, x2, and x3 are spare bits, usually logic one.

12. a is the remote LOF alarm bit, active high.

13. e1.e5 represent the CRC-5 check sequence. The entire 3156-bit multiframe, including the CRC-5

check sequence, should have a remainder of 0 when divided by x5 + x4 + x2 + 1.

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