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LM5145 Datasheet(PDF) 42 Page - Texas Instruments |
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LM5145 Datasheet(HTML) 42 Page - Texas Instruments |
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42 / 69 page ![]() In most cases, these actions are available: • Run electrical simulations to see important waveforms and circuit performance • Run thermal simulations to understand board thermal performance • Export customized schematic and layout into popular CAD formats • Print PDF reports for the design, and share the design with colleagues Get more information about WEBENCH tools at www.ti.com/WEBENCH. 10.2.1.2.2 Custom Design With Excel Quickstart Tool Select components based on the regulator specifications using the LM25143 Quickstart Calculator available for download from the LM25143 product folder. 10.2.1.2.3 Inductor Calculation 1. Use Equation 33 to calculate the required buck inductance for each channel based on a 30% inductor ripple current at nominal input voltages. IN(nom) OUT1 OUT1 O1 IN(nom) L SW IN(nom) OUT2 OUT2 O2 IN(nom) L SW V V V 3.3 V 12 V 3.3 V L 0.54 + V I F 12 V 2.1A 2.1MHz V V V 5 V 12 V 5 V L 0.66 + V I F 12 V 2.1A 2.1MHz § · § · ˜ ˜ ¨ ¸ ¨ ¸ ¨ ¸ ' ˜ ˜ © ¹ © ¹ § · § · ˜ ˜ ¨ ¸ ¨ ¸ ¨ ¸ ' ˜ ˜ © ¹ © ¹ (33) 2. Select a standard inductor value of 0.68 µH for both channels. Use Equation 34 to calculate the peak inductor currents at maximum steady-state input voltage. Subharmonic oscillation occurs with a duty cycle greater than 50% for peak current-mode control. For design simplification, the LM25143 has an internal slope compensation ramp proportional to the switching frequency that is added to the current sense signal to damp any tendency toward subharmonic oscillation. LO1 OUT1 OUT1 LO1(PK) OUT1 OUT1 O1 SW IN(max) LO2 OUT2 OUT2 LO2(PK) OUT2 OUT2 O2 SW IN(max) I V V 3.3 V 3.3 V I I I 1 7 A 1 7.94 A 2 2 L F V 2 0.68 + 0+] 9 I V V 5 V I I I 1 7 A 1 2 2 L F V 2 0.68 + 0+] § · § · ' ˜ ˜ ¨ ¸ ¨ ¸ ¨ ¸ ˜ ˜ ˜ ˜ © ¹ © ¹ § · ' ˜ ˜ ¨ ¸ ¨ ¸ ˜ ˜ ˜ ˜ © ¹ 5 V 8.27 A 18 V § · ¨ ¸ © ¹ (34) 3. Based on Equation 10, use Equation 35 to cross-check the inductance to set a slope compensation equal to the ideal one times the inductor current downslope. OUT S O1(sc) SW OUT S O2(sc) SW V (V) R (m ) 3.3 V 7m L 0.46 + 24 F (MHz) 24 2.1 MHz V (V) R (m ) 5 V 7m L 0.69 + 24 F (MHz) 24 2.1 MHz ˜ : ˜ : ˜ ˜ ˜ : ˜ : ˜ ˜ (35) 10.2.1.2.4 Current-Sense Resistance 1. Calculate the current-sense resistance based on a maximum peak current capability of at least 20% higher than the peak inductor current at full load to provide sufficient margin during start-up and load-on transients. Calculate the current sense resistances using Equation 36. LM25143 SNVSC10 – MARCH 2022 www.ti.com 42 Submit Document Feedback Copyright © 2022 Texas Instruments Incorporated Product Folder Links: LM25143 |
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