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LM5145 Datasheet(PDF) 42 Page - Texas Instruments

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Part # LM5145
Description  LM25143 3.5-V to 42-V Dual Synchronous Buck DC/DC Controller With Ultra-Low IQ
PDF  69 Pages
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Manufacturer  TI [Texas Instruments]
Direct Link  http://www.ti.com
Logo TI - Texas Instruments

LM5145 Datasheet(HTML) 42 Page - Texas Instruments

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In most cases, these actions are available:
• Run electrical simulations to see important waveforms and circuit performance
• Run thermal simulations to understand board thermal performance
• Export customized schematic and layout into popular CAD formats
• Print PDF reports for the design, and share the design with colleagues
Get more information about WEBENCH tools at www.ti.com/WEBENCH.
10.2.1.2.2 Custom Design With Excel Quickstart Tool
Select components based on the regulator specifications using the LM25143 Quickstart Calculator available for
download from the LM25143 product folder.
10.2.1.2.3 Inductor Calculation
1. Use Equation 33 to calculate the required buck inductance for each channel based on a 30% inductor ripple
current at nominal input voltages.
IN(nom)
OUT1
OUT1
O1
IN(nom)
L
SW
IN(nom)
OUT2
OUT2
O2
IN(nom)
L
SW
V
V
V
3.3 V
12 V
3.3 V
L
0.54 +
V
I
F
12 V
2.1A 2.1MHz
V
V
V
5 V
12 V
5 V
L
0.66 +
V
I
F
12 V
2.1A 2.1MHz
§
·
§
·
˜
˜
¨
¸
¨
¸
¨
¸
' ˜
˜
©
¹
©
¹
§
·
§
·
˜
˜
¨
¸
¨
¸
¨
¸
' ˜
˜
©
¹
©
¹
(33)
2. Select a standard inductor value of 0.68 µH for both channels. Use Equation 34 to calculate the peak
inductor currents at maximum steady-state input voltage. Subharmonic oscillation occurs with a duty cycle
greater than 50% for peak current-mode control. For design simplification, the LM25143 has an internal
slope compensation ramp proportional to the switching frequency that is added to the current sense signal to
damp any tendency toward subharmonic oscillation.
LO1
OUT1
OUT1
LO1(PK)
OUT1
OUT1
O1
SW
IN(max)
LO2
OUT2
OUT2
LO2(PK)
OUT2
OUT2
O2
SW
IN(max)
I
V
V
3.3 V
3.3 V
I
I
I
1
7 A
1
7.94 A
2
2 L
F
V
2 0.68 +
0+]
9
I
V
V
5 V
I
I
I
1
7 A
1
2
2 L
F
V
2 0.68 +
0+]
§
·
§
·
'
˜
˜
¨
¸
¨
¸
¨
¸
˜
˜
˜
˜
©
¹
©
¹
§
·
'
˜
˜
¨
¸
¨
¸
˜
˜
˜
˜
©
¹
5 V
8.27 A
18 V
§
·
¨
¸
©
¹
(34)
3. Based on Equation 10, use Equation 35 to cross-check the inductance to set a slope compensation equal to
the ideal one times the inductor current downslope.
OUT
S
O1(sc)
SW
OUT
S
O2(sc)
SW
V
(V) R (m )
3.3 V 7m
L
0.46 +
24 F
(MHz)
24 2.1 MHz
V
(V) R (m )
5 V 7m
L
0.69 +
24 F
(MHz)
24 2.1 MHz
˜
:
˜
:
˜
˜
˜
:
˜
:
˜
˜
(35)
10.2.1.2.4 Current-Sense Resistance
1. Calculate the current-sense resistance based on a maximum peak current capability of at least 20% higher
than the peak inductor current at full load to provide sufficient margin during start-up and load-on transients.
Calculate the current sense resistances using Equation 36.
LM25143
SNVSC10 – MARCH 2022
www.ti.com
42
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Product Folder Links: LM25143



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