AMD-K6 datasheet(225/346 Pages) AMD

225 / 346 page

Chapter 11

Test and Debug

207

20695H/0—March 1998

AMD-K6® Processor Data Sheet

Preliminary Information

L oadi n g 00 00 1b i n to the IR s h i f t regi s t er dur i ng the

Capture-IR state results in loading the SAMPLE/PRELOAD

instruction.

For each entry into the Shift-IR state, the IR shift register is

serially shifted by one bit toward the TDO pin. During the shift,

the most significant bit of the IR shift register is loaded from

the TDI pin.

The IR output register is loaded from the IR shift register in the

Update-IR state, and the current instruction is defined by the IR

output register. See “TAP Instructions” on page 211 for a list and

definition of the instructions supported by the AMD-K6.

Boundary Scan Register (BSR). The BSR is a Test Data Register

consisting of the interconnection of 152 boundary-scan cells.

Each output and bidirectional pin of the processor requires a

two-bit cell, where one bit corresponds to the pin and the other

bit is the output enable for the pin. When a 0 is shifted into the

enable bit of a cell, the corresponding pin is floated, and when

a 1 is shifted into the enable bit, the pin is driven valid. Each

input pin requires a one-bit cell that corresponds to the pin.

The last cell of the BSR is reserved and does not correspond to

any processor pin.

The total number of bits that comprise the BSR is 281. Table 38

on page 209 lists the order of these bits, where TDI is the input

to bit 280, and TDO is driven from the output of bit 0. The

entries listed as pin_E (where pin is an output or bidirectional

signal) are the enable bits.

If the BSR is the register selected by the current instruction

and the TAP controller is in the Capture-DR state, the

processor loads the BSR shift register as follows:

If the current instruction is SAMPLE/PRELOAD, then the

current state of each input, output, and bidirectional pin is

loaded. A bidirectional pin is treated as an output if its

enable bit equals 1, and it is treated as an input if its enable

bit equals 0.

If the current instruction is EXTEST, then the current state

of each input pin is loaded. A bidirectional pin is treated as

an input, regardless of the state of its enable.

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