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AD9545 Datasheet(PDF) 64 Page - Analog Devices

Part # AD9545
Description  Quad Input, 10-Output, Dual DPLL/IEEE 1588 1 pps Synchronizer and Jitter Cleaner
PDF  157 Pages
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Manufacturer  AD [Analog Devices]
Direct Link  http://www.analog.com
Logo AD - Analog Devices

AD9545 Datasheet(HTML) 64 Page - Analog Devices

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AD9545
Data Sheet
Rev. A | Page 64 of 157
TIME
NOMINAL
(50%)
Δt
MODULATION PERIOD (PM)
NOMINAL
(50%)
MODULATION MAGNITUDE
(D =
Δt/PQ)
Q DIVIDER
OUTPUT PERIOD (PQ)
Figure 55. Modulation Magnitude and Period
Modulation control consists of two parameters: Δt and PM.
Parameter Δt defines the desired magnitude of the modulation
edge variation, and PM defines the modulation period (see
Figure 55). The modulated signal consists of a time step of
magnitude Δt occurring at regular intervals of period, PM. The
magnitude parameter, Δt, is common to all the modulators
within a PLL channel, whereas the period parameter, PM, is
unique to each modulator.
MODULATION MAGNITUDE
To set the modulation magnitude use the 16-bit unsigned
Modulation step bit field in Register 0x10C0 to Register 0x10C1
and Register 0x14C0 to Register 0x14C1. The units associated
with the modulation step bit field are one-half of the period of
the input clock to the Q divider associated with the modulator,
yielding the following relationship:
D = Modulation step/(2 × Qxy)
(3)
where:
D is the duty cycle deviation (that is, the time deviation of the
modulation edge from nominal, normalized to the Q divider
output period). Figure 55 shows D as Δt/PQ.
Qxy is the divide ratio of the relevant Q divider (x is 0 or 1 and y
is A, B or C).
Because the modulation step bit field is common to all the
modulators in a PLL channel, whereas Qxy is unique to each
Q divider, D in Equation 3 is not necessarily the same for all the
modulators in a PLL channel.
Given the divide ratio for Q Divider Q0A is 1001, find the
modulation step bit field value necessary for Modulator A to
yield 5% modulation.
Modulation of 5% implies D = 0.05. Substituting the
appropriate values into Equation 3 yields
0.05 = Modulation step/(2 × 1001),
Therefore,
Modulation step = 100 (rounded to nearest integer)
= 0x64 (hexadecimal)
Given the same modulation step value as in the prececing
example (modulation step = 100), find the modulation magnitude
for Modulator B assuming Q0B has a divide ratio of 8025.5.
D = modulation step/(2 × Qxy)
= 100/(2 × 8025.5)
= 0.00623 (0.623%)
MODULATION PERIOD
The modulation period is the interval between modulation
events (see Figure 55). To control the modulation period
parameter, use the 28-bit unsigned Qxy modulation counter bit
field (where x is 0 or 1 and y is A, B or C) in Register 0x10C2 to
Register 0x10CD and Register 0x14C2 to Register 0x14C9. The
units associated with the Qxy modulation counter bit field is the
period of the output clock of the associated Q divider.
The Qxy modulation counter bit field has a constraint on its
minimum value:
Qxy modulation counter ≥ 6
The modulation period (PM) depends on the input clock
frequency (fIN), the divide ratio (Qxy_DIV) of the associated Q
divider and the value of the Qxy modulation counter bit field.
PM = Qxy modulation counter × (Qxy/fIN)
(4)
Suppose the input clock to Q Divider Q0A comes from APLL0
with its VCO operating at 2.38 GHz. Because the VCO drives
a divide-by-2 block prior to the Q divider clock input, the
Q divider input frequency (fIN) is 1.19 GHz. Find the value of
the Qxy modulation counter bit field required to yield a
modulation period (PM) of 1 ms (0.001 sec) for a Q divide ratio
(Qxy_DIV) of 107.5.
Substituting the appropriate values into Equation 4 yields
10−3 = Qxy modulation counter × (107.5/(1.19 × 109)),
Therefore,
Qxy modulation counter = 11,070 (nearest integer)
= 0x00002B3E (hexadecimal)



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